WebYou can do string=" abcdefg " string2=$ {string#" "} string2=$ {string2%" "} echo $string2 Or if your string length is constant, you can do string=" abcdefg " string2=$ {string:1:7} echo $string2 Also, this should work echo " abcdefg " cut -d " " -f 2 Also this echo " abcdefg " sed 's/^ \ (.*\) $/\1/' Share Improve this answer Follow

How to replace braces symbol in Linux - GeeksForGeeks

WebMay 5, 2011 · sed or awk command to replace a string pattern with another string based on position of this string. here is what i want to achieve... consider a file contains below … WebOct 26, 2016 · Use $ {var//pattern/} (or $ {var//pattern}) to replace with the empty string. You don't want to use echo to output arbitrary strings Except in zsh, variable expansions in list contexts have to be quoted the behaviour would be different compared to your sed approach when the variable contains newline characters. five thirty five election predictions

How to Find and Replace Text in a File Baeldung on Linux

WebApr 21, 2015 · 3 Answers Sorted by: 9 if ("$myVar" == "") then echo "the string is blank" endif Note that in csh, it is an error to attempt to access an undefined variable. (From a Bourne shell perspective, it's as if set -u was always in effect.) To test whether a variable is defined, use $?myVar: WebMar 11, 2024 · As we can see, sed is a quick and easy way to perform search and replace operations. 2.2. Find and Replace All Occurrences By default, sed only replaces the first occurrence that it finds. We can easily override this behavior to replace all instances within a file. Let’s see the expression that we can use to achieve this: WebJul 22, 2010 · the above code will replace all occurrences of the specified replacement term if you want, remove the ending g which means that the only first occurrence will be replaced. Share Improve this answer can i wear hiking shoes for walking